Grade 11 Physics: Troubleshooting Parts C and D

  • Thread starter Thread starter Shaley
  • Start date Start date
  • Tags Tags
    Grade 11 Physics
AI Thread Summary
The discussion focuses on troubleshooting physics problems related to a toboggan being dragged across snow. The kinetic energy of the toboggan is calculated as 67.6 J, while the work done by the applied force is corrected to 360 J. There is confusion regarding the calculation of thermal energy, with participants clarifying that it is primarily generated by friction, not potential energy. The thermal energy results from the conversion of energy due to friction, which increases the vibration of snow molecules, potentially causing melting. The conversation emphasizes the importance of understanding energy concepts and correcting misinterpretations in calculations.
Shaley
Messages
12
Reaction score
0
PARTS C AND D ARE WHAT I'M HAVING TROUBLE WITH.

a tobaggan of mass 20kg is dragged horizontally across snow by someone who exerts a force of 45N. the tobaggan travels 8m under the action of the force and has a final speed of 2.6 m/s.
a)calculate the actual kinetic energy of the tobaggan based on its speed

Ek=1/2mv^2
=1/2(20)(2.6)
=67.6J

b)Calculate the amount of work actually done on the tobaggan by the applied force

W=F X d
=450X8
=3600J

c)From your answers to parts a and b, calculate the amount of thermal energy generated.

Ethermal=Ekinetic + Epotential
I know that potential =3600J from b (the actual work done), but what's the potential - would it be a's answer of 67.6?

d)Explain how this thermal energy was generated and state one effect it might have.

I think that it was generated by the friction caused between the tobagganand the snow, which the tobagan was being dragged.the effect is the the friction would cause a transfer of kinetic energy into the snow molecules. This increased vibration of snow molecules will cause and increase in the total energy, or thermal energy, which will cause the snow to melt. IS THIS RIGHT? THANKYOU.
 
Physics news on Phys.org
Shaley said:
PARTS C AND D ARE WHAT I'M HAVING TROUBLE WITH.

a tobaggan of mass 20kg is dragged horizontally across snow by someone who exerts a force of 45N. the tobaggan travels 8m under the action of the force and has a final speed of 2.6 m/s.
a)calculate the actual kinetic energy of the tobaggan based on its speed

Ek=1/2mv^2
=1/2(20)(2.6)
=67.6J

b)Calculate the amount of work actually done on the tobaggan by the applied force

W=F X d
=450X8
=3600J
that's 45 x 8 = 360 J, typo error
c)From your answers to parts a and b, calculate the amount of thermal energy generated.

Ethermal=Ekinetic + Epotential
this equation is not correct; thermal energy is often just the heat energy generated by the work done by friction
I know that potential =3600J from b (the actual work done), but what's the potential - would it be a's answer of 67.6?
I think you are misunserstanding the concept of potential energy. Potential energy is generally associated witht the ability of gravity or spring forces to do work. 67.6 is the kinetic energy (of motion).
d)Explain how this thermal energy was generated and state one effect it might have.

I think that it was generated by the friction caused between the tobagganand the snow, which the tobagan was being dragged.the effect is the the friction would cause a transfer of kinetic energy into the snow molecules. This increased vibration of snow molecules will cause and increase in the total energy, or thermal energy, which will cause the snow to melt. IS THIS RIGHT? THANKYOU.
That's not quite correct; I wouldn't use the term kinetic energy, just say energy; and total energy of a system cannot either increase or decrease. The thermal energy was generated by ________? To calculate it, are you familiar with the work-energy or conservation of energy principles?
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top