Gradient of a Vector Function in Other Co-ordinate Systems

DylanB
Messages
52
Reaction score
0

Homework Statement


I am trying to figure out how to take the gradient of a vector function in polar and spherical co-ordinates.


Homework Equations





The Attempt at a Solution


I am aware of how the gradient of a vector function in cartesian co-ords looks, simply the second order tensor


<br /> (\boldsymol{\nabla}\mathbf F)_{ij} = \frac{\partial F_i(\boldsymbol x)}{\partial x_j}


I am having trouble extending this idea to polar and spherical co-ords. The del operator is easy enough to derive in different co-ordinates but finding the second order tensor I am having difficulties.
 
Last edited:
Physics news on Phys.org
Any luck figuring out how to take a gradient of a vector field in spherical coordinates? I am also stumped on this and would appreciate any insight you have. Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top