Graphing a Polar Function: Solving for r = 2cosθ

Click For Summary
SUMMARY

The discussion focuses on graphing the polar function r = 2cos(θ) for the interval -π/2 ≤ θ ≤ π/2. Participants confirm that this function traces a full circle of unit radius centered at (1,0). The solution involves deriving parametric equations using double angle identities, specifically x - 1 = cos(2θ) and y = sin(2θ), which demonstrate that as θ varies through π radians, the entire circle is traced. Additionally, the concept of symmetry in polar coordinates is highlighted as a method to complete the graph.

PREREQUISITES
  • Understanding of polar coordinates and their graphical representation
  • Familiarity with trigonometric functions and identities
  • Knowledge of parametric equations
  • Basic concepts of symmetry in mathematical graphs
NEXT STEPS
  • Study polar coordinate systems and their properties
  • Learn about parametric equations and their applications in graphing
  • Explore trigonometric identities, particularly double angle formulas
  • Investigate symmetry in polar graphs and its implications
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone interested in graphing polar functions and understanding their properties.

physicsnewb7
Messages
42
Reaction score
0

Homework Statement



graph the polar function r=2cos\theta (-\pi/2 \leq \theta \leq \pi/2) sorry that last theta/2 should be pi/2. new to this math text

Homework Equations





The Attempt at a Solution


I graphed the positive part right, I think. it seems to trace a half circle. I get confused when it comes to the negative radians. what would this trace out in full. Excuse me but its been a while since trig.
 
Physics news on Phys.org
You should get a full circle of unit radius, centered at (1,0). The easiest way to see that \frac{-\pi}{2}<\theta<\frac{\pi}{2} traces out the entire circle is to find parametric equations for x-1 and y and use the double angle identities. You should find that x-1=\cos(2\theta) and y=\sin(2\theta) and so as theta moves through pi radians, (x-1) and y both move through a full period, tracing out the entire circle.
 
I think an even easier way once you find part of the graph is use symmetry. If you can replace theta by negative theta then there is symmetry with respect to the polar axis and the circle is completed.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K