Graphing a Trajectory with Variable Gravity

[peterk]

Homework Statement

I would like to graph the position, velocity, and acceleration curves (over time) of an object that is launched straight up from the surface of the Earth, but I need to take into account the fact that the Earth's gravitational pull weakens as the object gets higher.

The position-time graph of an object launched at escape velocity should only go up and never down.

Homework Equations

g(r / s)2 = the acceleration of gravity at height s above the center of the Earth (where s > r ).
x(t)=(1/2)*a*t^2+v0*t+x0

The Attempt at a Solution

x(t)=(1/2)*-9.8*t^2+11184*t+0 (assuming that escape velocity is 11184). This would work except there is less gravity as the object moves farther away from the Earth, so it should never really return to the Earth's surface.

 

[andrevdh]

From

a_y = ky^{-2}

we progress to

\frac{d\ v_y}{dt} = ...

and then to

\frac{d\ v_y}{dy}\ \frac{d\ y}{dt} = ...

which gives

v_y\ \frac{d\ v_y}{dy} = ...

integrating this gives

\int {v_y\ dv_y} = k\int {y^{-2}dy}

...