Graphing Linear Equations: Finding Intercepts

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To graph the linear equation y = 3x - 2, start by finding the y-intercept by setting x to zero, resulting in the point (0, -2). Next, determine the x-intercept by setting y to zero, which gives the point (2/3, 0). With these two points identified, plot them on the graph and connect them with a straight line. The slope of 3 indicates that the line will rise as it moves from left to right. This method effectively illustrates the linear relationship defined by the equation.
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How would I go about graphic this?

y = 3x - 2
 
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As you alluded to in the subject of your post, a good way to graph the equation is to find the y intercept; and graph from there knowing the slope is 3. So set x to zero and determine the y intercept that way, then simply use the slope's ratio (3/1) and remember "rise over run".
 
Or you can realize it is a linear equation and just take any two points, graph them, and connect them with a straight line.
 
all you do is find the two intercepts and join them together...
remember that to find...
y-intercept, let x = 0 and
x-intercept, let y = 0...

so y-intercept = y = 3(0) - 2
y-int = -2
therefore ... (0,-2)

and x-intercept = 0 = 3x-2
3x = 2
x = (2/3)

(2/3,0)

so then you put a dot on those points and draw a line.
the line should be increasing since you know that the gradient is positive.
 
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