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Graphing the y intercept?

  1. Jul 10, 2004 #1
    How would I go about graphic this?

    y = 3x - 2
     
  2. jcsd
  3. Jul 10, 2004 #2

    Gza

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    As you alluded to in the subject of your post, a good way to graph the equation is to find the y intercept; and graph from there knowing the slope is 3. So set x to zero and determine the y intercept that way, then simply use the slope's ratio (3/1) and remember "rise over run".
     
  4. Jul 11, 2004 #3
    Or you can realize it is a linear equation and just take any two points, graph them, and connect them with a straight line.
     
  5. Jul 11, 2004 #4
    all you do is find the two intercepts and join them together...
    remember that to find...
    y-intercept, let x = 0 and
    x-intercept, let y = 0...

    so y-intercept = y = 3(0) - 2
    y-int = -2
    therefore ... (0,-2)

    and x-intercept = 0 = 3x-2
    3x = 2
    x = (2/3)

    (2/3,0)

    so then you put a dot on those points and draw a line.
    the line should be increasing since you know that the gradient is positive.
     
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