How would I go about graphic this?
y = 3x - 2
As you alluded to in the subject of your post, a good way to graph the equation is to find the y intercept; and graph from there knowing the slope is 3. So set x to zero and determine the y intercept that way, then simply use the slope's ratio (3/1) and remember "rise over run".
Or you can realize it is a linear equation and just take any two points, graph them, and connect them with a straight line.
all you do is find the two intercepts and join them together...
remember that to find...
y-intercept, let x = 0 and
x-intercept, let y = 0...
so y-intercept = y = 3(0) - 2
y-int = -2
therefore ... (0,-2)
and x-intercept = 0 = 3x-2
3x = 2
x = (2/3)
so then you put a dot on those points and draw a line.
the line should be increasing since you know that the gradient is positive.
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