Where Is Zero Gravity Between Earth and Moon?

AI Thread Summary
The discussion centers on identifying the point between Earth and the Moon where gravitational forces cancel each other out, resulting in zero weight for an object. It clarifies that the ratio of the Moon's gravity to Earth's gravity (1/6) does not directly translate to the distance from the Moon where this balance occurs. Instead, participants emphasize the need to use gravitational force equations to accurately determine this point. Ultimately, the calculated position for zero gravity is found to be 1/10 of the total distance from the center of the Moon. This highlights the importance of mathematical analysis in understanding gravitational interactions in space.
nilic1
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Where on an imaginary gravitational field line between Earth and moon, a mass would have no weight neither due Earth nor due to moon?
 
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If you mean when the gravitational force is zero, then you just need to equate

FEarth and FMoon for a mass m and solve for the distance.
 
rock.freak667 said:
If you mean when the gravitational force is zero, then you just need to equate

FEarth and FMoon for a mass m and solve for the distance.

Thanks for your reply. This was meant to be a straight forward answer without any calculation.
Since the gravity of the moon is 1/6 that of Earth , does it follow that the distance where there is no gravity on the object is 1/6 the distance between moon and Earth, starting off from the moon?
 
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No, that 1/6 figure is only true about the surface gravity of the Earth vs. the surface gravity of the moon. It is not applicable everywhere in space.

I think you really do need to set up an equation using the equation for gravitational force. At least, I can't imagine solving it any other way.
 
Redbelly98 said:
No, that 1/6 figure is only true about the surface gravity of the Earth vs. the surface gravity of the moon. It is not applicable everywhere in space.

I think you really do need to set up an equation using the equation for gravitational force. At least, I can't imagine solving it any other way.

Thanks for you answer. I did as you both suggested. The final answer is 1/10 the total distance starting from the centre of the moon.

Regards
 

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