Gravitational field strength of the earth

Thread starter AbsoluteZer0
Start date Oct 23, 2012
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Earth Field Field strength Gravitational Gravitational field Gravitational field strength Strength

AI Thread Summary

The calculation of 'g' using the formula g = GM/r² resulted in a value of 9.792121683 N/kg, which is close to the standard value of 9.8 N/kg. The discrepancy may arise from unit conversion, particularly if the Earth's radius was mistakenly squared in kilometers instead of meters. Ensuring proper unit consistency is crucial in such calculations. The discussion emphasizes the importance of double-checking units to avoid errors. Accurate calculations are essential for reliable results in physics.

Oct 23, 2012

AbsoluteZer0

Hi,

Using the formula g = \frac{GM}{r<sup>2</sup>} I found 'g' to equal (9.792121683 x 10⁶ \frac{N}{kg})

The value of g is 9.8 \frac{N}{kg}. I am wondering if I made an error in my calculations or if there is a method of simplifying to get 9.8.

Thanks,

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Oct 23, 2012

D H

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Units. Always check your units. You most likely divided by the square of the Earth's radius in kilometers.

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