Gravitational force = 0 between two planets?

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SUMMARY

The discussion centers on calculating the position of an object placed between a planet of mass M and its moon of mass m, where the net gravitational force on the object is zero. The gravitational force equation, Fg = G(Mm/R^2), is utilized, leading to the equation M/d^2 = m/(R-d)^2. The solution involves solving this quadratic equation to find the distance d from the center of the planet. The approach and calculations presented are confirmed as correct by participants in the discussion.

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Which is the answer?

  • ((M-m)/(M+m))R

    Votes: 0 0.0%
  • (M+m)/(M-m)

    Votes: 0 0.0%
  • (((M^.5)+(m^.5))/(M-m)) * (M^.5) R

    Votes: 0 0.0%
  • (((M-m)/(M+m))^.5) * R

    Votes: 0 0.0%
  • (((M^.5)-(m^.5))/(M-m)) * (M^.5) R

    Votes: 0 0.0%

  • Total voters
    0
  • Poll closed .
Hayden_
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Homework Statement



A planet of mass M has a moon of mass m in a circular orbit of radius R. An object is placed between the planet and the moon on the line joining the center of the planet to the center of the moon so that the net gravitational force on the object is zero. How far is the object placed from the center of the planet?

Homework Equations



Fg=G(Mm/R^2)

I used the variable d to describe how far the object is placed from the center of the planet

The Attempt at a Solution



G(M(mass of object))/d^2 = G(m(mass of object))/(R-d)^2

G and mass of object cancel out

M/d^2 = m/(R-d)^2
 
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find d.?
 
Looks good to me!

Hi Hayden! Welcome to PF :smile:

Hayden_ said:
M/d^2 = m/(R-d)^2

Looks good to me!

Now all you have to do is to solve the quadratic equation … :smile:
 

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