Gravitational Force (Earth and Sun)

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SUMMARY

The discussion focuses on calculating the required thickness of a steel cable that would replace gravitational force between the Earth and the Sun. The tensile strength of steel is given as 5.1 x 10^8 N/m². The initial calculations provided by the user resulted in a thickness of 465.45 meters, which was deemed incorrect. The correct approach involves equating the centripetal force to the tensile strength divided by the cross-sectional area of the cable.

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  • Understanding of gravitational force and circular motion principles
  • Familiarity with tensile strength and material properties of steel
  • Knowledge of basic physics equations related to force and area
  • Ability to manipulate algebraic equations for problem-solving
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jgens
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Homework Statement



To better comprehend the gravitational force between the Earth and the Sun, pretend gravity is turned off and the pull replaced by the tension in a steel cable joining them. How thick would such a cable need to be? You can estimate the diameter by knowing the tensile strength of steel cable is about 5.1 * 10^8 N/m^2.



Homework Equations



Any equations concerning gravitation/cirular motion.

The Attempt at a Solution



This is my attempt at a solution, the answer key says it's wrong.

F = m(4)(pi^2)(r)/t^2

d^2 = m(4)(pi^2)(r)/(t^2)(tensile strength)

thickness = m(4)(pi^2)/(t^2)(tensile strength)

thinkness = 465.45 m or 0.465 km

Where have I gone wrong in my calculations? Can someone please steer me in the right direction. Thanks.
 
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jgens said:
F = m(4)(pi^2)(r)/t^2

OK.

d^2 = m(4)(pi^2)(r)/(t^2)(tensile strength)

Didn't understand.

Try to think simply.

Max tensional force/cross-sectional area of cable = tensile strength =>
Centripetal force/area = tensile strength.
 

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