Gravitational Potential Energy

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When a stone is thrown upwards with escape velocity, its velocity and gravitational potential energy approach zero over time, leading to confusion about energy conservation. The energy expended in throwing the stone does not disappear; it is transformed into gravitational potential energy as the stone moves away from Earth. This potential energy is considered "stored" energy, which can be converted back to kinetic energy if the stone is pulled back towards Earth. The formula for gravitational potential energy indicates that the total energy is zero at infinite distance, but this does not account for the initial work done. Ultimately, the energy used in throwing the stone is accounted for in the overall energy balance, reinforcing the principle of energy conservation.
J. Richter
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Hi.

I am a little confused about this:

If I throw a stone straight upwards from the surface of the Earth, with the escape speed of 11,2 km/s, assuming that no air or other particles gets in the way, and waited for a very, very long time, the velocity of my stone (and the Earth in the opposite direction) would be almost 0, and the gravitational potential energy between my stone and the Earth would be almost 0 as well, according to the formula for gravitational potential energy.

However I used a lot of energy to throw that stone.
That energy I used to actually do some work, must be stored somehow, as it can’t disappear.

It is obvious, that the energy is stored in this “end” scenario itself.
If something far out there in space gave the stone a tiny little push towards the Earth, it would accelerate “backwards”, until it reaches 11,2 km/s, hit the surface of the Earth, and converts it’s kinetic energy to heat.

This kind of “stored” energy that the two masses have, when being far away from each other, to make it up for the loss of energy in my muscles after throwing the stone, appears to be different from the potential energy described in the formula for gravitational potential energy.

And that’s what confuses me.

If we can’t call this additional “stored” energy for potential energy between the masses, what can we call it then? And why does the formula for gravitational potential energy say that the resulting energy in this “throwing stone“ thought experiment is 0, when I actually did some work on the stone while throwing it?

That seems to be the same as saying, that the energy I used is lost forever.
 
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J. Richter said:
This kind of “stored” energy that the two masses have, when being far away from each other, to make it up for the loss of energy in my muscles after throwing the stone, appears to be different from the potential energy described in the formula for gravitational potential energy.
Why do you think that? That "stored" energy is gravitational potential energy.

And that’s what confuses me.

If we can’t call this additional “stored” energy for potential energy between the masses, what can we call it then? And why does the formula for gravitational potential energy say that the resulting energy in this “throwing stone“ thought experiment is 0, when I actually did some work on the stone while throwing it?
You have to compare the final energy of 0 to what you started with. Gravitational PE between two objects is given by:

-\frac{Gm_1m_2}{r}

It is negative for finite distances. Thus the work you did on the stone increases the total energy to 0.
 
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