Gravity of Torus: Understand Its Impact on Shape & Movement

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A perfect sphere placed at the center of a torus would remain stationary if the torus is uniformly dense and everything else is stationary. The gravitational effect experienced while walking on a torus depends on the size of the hole and the distribution of mass. As one approaches the center of the torus, gravity from the opposite side could influence the experience, but this effect is complex and requires detailed calculations using the inverse square law. The overall gravitational impact is determined by the total mass of the torus and its geometry. Understanding these principles is crucial for analyzing movement and shape in relation to gravitational forces in a toroidal structure.
energyflash
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Hi!

This may not be the right place for it but I have a question about the torus.

In the centre point, the exact middle of the hole in the torus if a let's say, a perfect sphere was placed there, would it simply stay in the one place if everything was stationary?

Also could you walk all over a torus without the gravity of one area affecting another, or would this depend on the size of the hole? For example if you were walking toward the inside of the torus, when you got to the exact middle point, would you be affected by the gravity on the opposite side of the hole to where you are standing?
 
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a torus is like a doughnut right?
 
In the centre point, the exact middle of the hole in the torus if a let's say, a perfect sphere was placed there, would it simply stay in the one place if everything was stationary?
yes, assuming uniform density of the torus.

As for your other question, the gravity at any point is the sum (integral) of all the mass of torus, using the inverse square law. It is a fairly complicated calculation.
 
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