Gyroscope coupling force force question

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SUMMARY

The discussion centers on the forces acting on a gyroscope, specifically regarding the momentum that prevents a gyroscope from falling and the calculation of the force required to bring it down while maintaining constant RPM from an electric motor. The user, Sharon, references a video and a website on gyroscopes to seek clarification on the omega component and its relationship to coupling force. The inquiry highlights a misunderstanding of angular momentum and its implications in gyroscopic motion.

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Hello everyone,

I saw this video in youtube:
And I have some questions, can someone please explain me the forces acting on this gyro? what is the momentum that keeps the cheese from falling, the direction of its action don't add up to me

Also, how could i calculate the force needed to take down the cheese to the ground given that the RPM is constant (electric motor), unlike in the video above?

i tried using the following website after reading about gyros:
http://www.gyroscopes.org/math.asp
what i don't understand is the omega part, it seems to be zero in the youtube video so how come the coupling force is so big?

Thanks a lot,
sharon
 
Last edited by a moderator:
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no one? realy?
is it like holiday now or something? :-)
 

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