Half controlled single bridge rectifier

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In a half controlled single bridge rectifier supplying an R-L load, the discussion centers on determining the fraction of the cycle that the freewheeling diode conducts. Initially, one participant suggests that each diode conducts for half the cycle, leading to an answer of 1/2, but the book states the answer is alpha/pi. Clarification reveals that the freewheeling diode is typically the one directly across the load, which allows for continuous load current due to inductance. The book's explanation details that during specific intervals, only one diode is in freewheeling mode, resulting in the fraction being alpha/pi. The conversation highlights differing interpretations of freewheeling diodes and their role in the rectification process.
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Homework Statement


A half controlled single bridge rectifier is supplying an R-L load. It is operated at firing angle 'alpha'. Load current is continous. What is fraction of cycle that the freewheeling diode conducts?

Homework Equations


upload_2016-12-1_14-52-25.png

The Attempt at a Solution


Well I guess each diode will conduct for half the cycle like from 0 to pie and then from pie to 2 pie, the other diode will conduct.
So the answer must be 1/2. But book answer is alpha / pie.[/B]
 

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None of the 4 devices shown in your OP is a free-wheeling diode. Why is there no such diode shown in a question that apparently refers to it? :oldconfused:
 
I thought FWD are the diodes D1 and D2. As per first diagram in the link:
http://www.technik-emden.de/~elmalab/projekte/ws9899/pe_html/ch06s1/ch06s1p1.htm

and book diagram:
upload_2016-12-1_17-7-20.png
 
FWD in your attachment is a freewheeling diode.
 
So it's a diode parallel to RL load with anode of diode towards up and cathode facing down.
Thanks.
 
If load current is continuous, then the diodes in the rectifier must share conduction equally and your original answer would have to be right.

There is "freewheeling" operation due to the load inductance, otherwise load current could not be continuous. But I am not sure whether the 2 diodes that form half of the bridge are usually referred to as freewheeling diodes, though. I'll have to look at this more closely.

It's the diode directly across the load that I think of as the classic freewheeling diode.
 
I tried with ur concept of FWD and got this answer as:
upload_2016-12-1_18-58-36.png

upload_2016-12-1_18-59-33.png


Thus i get the book answer.
Book has also given another explanation. They have taken fwd as diode D1 and D2.
They said that from
1) from alpha to pie, current flows through T1, load, D2
2) from pie to pie + alpha, current flows from T1 load, D1
So D1 is in freewheeling mode only in second case. Duration is pie + alpha - pie which is alpha. This happens in each half cycle of sine wave, so twice in full cycle.
Fraction is 2 * alpha divide by 2 * pie which gives alpha/pie.

But i like first explanation of mine better where ur concept of FWD is used. Thanks..
 

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