Half-Life Calculation: How Do Physicists Measure Isotopes?

Danscall
Messages
1
Reaction score
0
Hi there,

Someone asked me this earlier when we were talking about radioisotope dating. How do physicists determine the half lives of isotopes when said half life stretches into the millions of years?

Random question I know :P

-Dan
 
Physics news on Phys.org
It's not hard to do this. The reason we can do this is that atoms are so small that a macroscopic sample of some isotope contains a huge number of them. So if I have a gram of U-238, for example, with a half-life of 4.5 billion years, I would need to wait 4.5 billion years for half of it to decay. But a gram of U-238 contains (6.02x10^23)/238 ~ 10^21 atoms. So even though the probability of a single nucleus decaying is quite small, in a gram about 12,000 nuclei will decay every second. This can be easily measured, and from the number that decay every second, we can calculate the half-life. The number that decay every second is called the "activity". Try reading these:

http://en.wikipedia.org/wiki/Radioactive_decay
http://en.wikipedia.org/wiki/Half-life
 
Danscall said:
Hi there,

Someone asked me this earlier when we were talking about radioisotope dating. How do physicists determine the half lives of isotopes when said half life stretches into the millions of years?

Random question I know :P

-Dan
One can measure an activity and from that a decay constant. One can also measure the daughter isotopes and from that determine a rough estimate of where in the decay time the particular radionuclides are. However, this requires an assumption about the original composition.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Back
Top