Hall effect sensor - 480-5198-ND - Question

AI Thread Summary
The discussion focuses on modifying the behavior of the Hall effect sensor model 480-5198-ND, which is currently "ON" by default and "OFF" when a magnet is near. To achieve the desired functionality of being "OFF" by default and "ON" when the magnet is present, a common-emitter NPN transistor stage can be used to invert the output signal. This configuration allows the input signal to control the transistor, resulting in an inverted output. Additionally, there is a request for guidance on calculating resistor values R1 and R2 for the circuit. Understanding the common-emitter inverter circuit is essential for implementing this solution effectively.
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Homework Statement


I am using the a hall effect sensor - model 480-5198-ND. I have tested this simple circuit using a LED and it is working. However, it is "ON" by default. Only when the magnet is near the hall effect sensor , it will be "OFF".

How do I make it such that it is OFF by default and ON only when the magnet is near the hall effect sensor?

Homework Equations

The Attempt at a Solution


http://[ATTACH=full]199957[/ATTACH]
 

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The A in my diagram means that it is connected to the LED.
 
Follow it with a common-emitter NPN transistor stage to invert the output signal. Does that make sense?
 
Can I have some explanation why it is able to invert the signal?
 
May I know how do I calculate the value of R1 and R2?
 
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