[See the figure attached]
a) Find the relation between velocity of electron v and current I.
b) Because of the magnetic force on the electron they move at the edge of
conductor as shown in the figure and create a electrostatic force that oppomagnetostatic force. Find the expression for electrostatic force and magnetforce when they balance each other.
c) At equilibrium find an expression for Hall voltage V
in terms of magneelectron’s velocity v and width d.
Now, in a Hall-effect experiment, a current of 3.0 A sent lengthwise through a co1.0 cm wide, 4.0 cm long, and 10 mm thick produces a transverse (across the wpotential difference of 10 mV when a magnetic field of 1.5 T is passed perpendihrough the thickness of the conductor. From these data, find the number of elper unit volume of the conductor.
The Hall effect is the production of a voltage difference (the Hall voltage) across
an electrical conductor, transverse to an electric current in the conductor and a magnetic
field perpendicular to the current..The magnetostatic force acting on a moving charge passing through uniform magnetic field is given by,F = qvB. Where, B = magnetic field strength (unit Tesla), v =
velocity of charged particle that is perpendicular to the magnetic field lines. F is
perpendicular to both velocity and magnetic field.
The Attempt at a Solution
Hall Voltage seems different from the normal textbook voltage problems that I have encountered. So, I couldn't make some satisfactory advancement.