Hanging swing fair ride

  • Thread starter robdawg
  • Start date
  • #1
2
0
hello all this is my first post. I need to know the time to do one complete revolution around the pole.

.........m
I------------------
I........I.........θ......\
I........I..................\
I........I....................\..n
I.............................[]
I
I

m = 3 meters
n = 5 meters
θ = 30
[] = swing
 

Answers and Replies

  • #2
Integral
Staff Emeritus
Science Advisor
Gold Member
7,201
56
Draw a free body diagram, identify the centripetal force acting, Then apply newtons laws to find the radial component of acceleration. Use the relationship between the angluar velocity and the radial component of acceleration to determine the angular velocity.
 
  • #3
2
0
here's what I know so far by doing a free body diagram.
5cos(30)= y
length y = Sqrt(18.75)
5sin(30) = x
length x = 2.5
R = 3 + 2.5 = 5.5

using the pythagorean thereom we now that

sqrt((2.5)^2 + 18.75) = 5

force y = tcos(30)
force x = tsin(30)

circumference = 2pi(R)

about the forces we know that 5cos(30) = mg
and that tsin(30) = mω^2R

now how do I get rpms from this? what do I solve for?

thanks
 
Last edited:
  • #4
Integral
Staff Emeritus
Science Advisor
Gold Member
7,201
56
ω is the rotational velocity in Radians/second. One revolution is 2Π Radians so to get RPM = 2Πω*60
 

Related Threads on Hanging swing fair ride

  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
3
Views
5K
Replies
7
Views
1K
  • Last Post
Replies
2
Views
2K
Replies
5
Views
4K
Replies
14
Views
3K
Replies
5
Views
1K
  • Last Post
Replies
1
Views
2K
Top