Hard power series and initial value problem question

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SUMMARY

The discussion focuses on solving the initial value problem dy/dx = y with the condition y(0) = A using power series. The solution is represented as a power series y(x) = Σ (an)(x^n) from n=0 to infinity. By differentiating this series term-by-term and equating it to y, participants derive relationships between the coefficients an and an-1, ultimately leading to the conclusion that y(x) = Ae^x. The key steps include finding a0, deriving the power series for dy/dx, and establishing a formula for an.

PREREQUISITES
  • Understanding of power series representation
  • Knowledge of derivatives and their application to series
  • Familiarity with the exponential function and its series expansion
  • Basic skills in solving initial value problems
NEXT STEPS
  • Study the derivation of power series coefficients from differential equations
  • Learn about the Taylor series expansion for e^x
  • Explore methods for solving initial value problems using series solutions
  • Investigate the relationship between power series and ordinary differential equations
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Students studying calculus, particularly those focusing on differential equations and power series methods, as well as educators looking for teaching strategies in these topics.

calculusisrad
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Homework Statement



We know that y = Aex is the solution to the initial value problem dy/dx = y; y(0) = A.
This can be shown by solving the equation directly. The goal of this problem is to reach the same conclusion using power series.
Method: Let y be a solution to the initial value problem, and suppose y has the
power series representation
y(x) =the sum from n= 0 to n= infinity of (an)(x^n)
which equals a0 + a1x + a2x^2 + ...

First finnd a0. Next, take the term-by-term deriviative of the series to fi nd a power
series representation for dy/dx . Using the fact that dy/dx = y, obtain a formula which
shows how an is related to an-1 for n >1. From this, find an explicit formula for an.
Finally, use the known power series representation for e^x to conclude that y(x) = Ae^x


The Attempt at a Solution



I know an = f(n)(0)/n!
And I know the function is a power series centered at 0.
but I don't really know where to go from there?
i just don't know where to start on this. please help. if I see how to get started, I will be able to understand. I did try, but I don't know what to do!
 
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calculusisrad said:

Homework Statement



We know that y = Aex is the solution to the initial value problem dy/dx = y; y(0) = A.
This can be shown by solving the equation directly. The goal of this problem is to reach the same conclusion using power series.
Method: Let y be a solution to the initial value problem, and suppose y has the
power series representation
y(x) =the sum from n= 0 to n= infinity of (an)(x^n)
which equals a0 + a1x + a2x^2 + ...

First finnd a0. Next, take the term-by-term deriviative of the series to fi nd a power
series representation for dy/dx . Using the fact that dy/dx = y, obtain a formula which
shows how an is related to an-1 for n >1. From this, find an explicit formula for an.
Finally, use the known power series representation for e^x to conclude that y(x) = Ae^x


The Attempt at a Solution



I know an = f(n)(0)/n!
And I know the function is a power series centered at 0.
but I don't really know where to go from there?
i just don't know where to start on this. please help. if I see how to get started, I will be able to understand. I did try, but I don't know what to do!

If the solution can be represented as:

[tex]y(x)=a_0+a_1 x+a_2 x^2+\cdots[/tex]

and you know y(0)=A, then you know what a_0 is then and when you take the derivative of y(x), it's

[tex]y'(x)=a_1+2a_2 x+3 a_3x^3+\cdots[/tex]

and since you're given y'=y, then what about equating the respective power series for y'=y then equating coefficients? Doing that, can't you find an explicit expression for a_n? I'll do two:

[tex]a_1=A[/tex]
[tex]2a_2=a_1[/tex]

but since a_1=A then [itex]a_2=\frac{a_1}{A}[/itex]. Now do a few more and notice the trend. Then come up with the general expression for a_n.
 

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