Hard QCD Processes: Definition & Overview

  • Thread starter Thread starter Ancient_Nomad
  • Start date Start date
  • Tags Tags
    Hard Qcd
Ancient_Nomad
Messages
15
Reaction score
0
What are Hard QCD processes ?
 
Physics news on Phys.org
hard means perturbative, i.e. processes which one can calculate using perturbation theory = momentum transfer is larger than around 250 GeV. At this energy, the QCD coupling constant becomes "large" so that perturbation theory is no longer valid.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Replies
1
Views
1K
Replies
38
Views
5K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
5
Views
2K
Replies
22
Views
4K
Back
Top