Hardy Weinberg Principle: Calculating Allele Frequency in a Fish Population

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In a fish population of 300 individuals, 40 have red eyes (dominant allele) and 260 have blue eyes (recessive allele). To calculate allele frequencies using the Hardy-Weinberg principle, the equations p² + 2pq + q² = 1 and p + q = 1 are utilized. The correct approach involves determining q as the frequency of the blue allele, which can be calculated from the proportion of blue-eyed fish. The discussion emphasizes that the fraction of red-eyed fish does not directly equal p, and expressing blue-eyed fish in terms of q simplifies the calculation. Understanding these relationships is crucial for accurately determining allele frequencies in the population.
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Homework Statement



In a population on fish, 40 have red eyes and 260 have blue eyes. Allele for red is dominant over blue alleles. Use hardy Weinberg principle to calculate the frequency of the white and red allele.

Homework Equations



p2 + 2pq + q2 = 1

q + p = 1

The Attempt at a Solution



p = 96.67 %

i took 40 and divided it by 300 and for 13.3% as my answer. but i got it wrong...I'm pretty much stuck, help?
 
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Assuming p is the frequency of the dominant allele, can you use p & q to express what fraction of the population has red eyes?

Note: \frac{40}{300} is the fraction of the population with red eyes, but it is not equal to p.
 
It is also helpful is to express the fraction of the population that has blue eyes in terms of q.
 
Ygggdrasil said:
It is also helpful is to express the fraction of the population that has blue eyes in terms of q.

Good point. Much simpler than what I attempted to do.
 
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