Harmless Lorentz transformation question

  • #101
Physicsguru said:
My question is simple.

If, after time amount of time \Delta t has elapsed according to some clock which is permanently at rest in S, the photon has coordinates (L,0,0) in frame S, what is my x` coordinate in frame S`?

For the sake of definiteness, suppose that exactly one second has ticked according to a clock at rest in frame S. Therefore, the location of the photon in frame S is given by (299792458 meters, 0,0).

Let (M,0,0)` denote the location of the origin of inertial reference frame S, in reference frame S`, at the instant that the clock at rest in frame S strikes one. Solve for M.

Guru

I read all arguments, but then finally what is the answer to the first question raised by Guru?

What is M? and
(I am adding this) What is the speed of the photon in the frame S'?!

How I feel the question can be answered (possible ways) are:

a) Give exact values for M and Vs'
b) Give probability distribution of possible values for M and Vs'
c) Assert and prove that the Conceptualization of a reference frame attached to the photon, is meaningless and thus refrain from answering the question. (Here whether lorentz transformation holds good in that reference frame is besides the question as we do have some thing (photon) which moves at 'c' the lorentz constant and in our minds we can think of it as a reference frame. What I feel one needs to prove here is that thought is meaningless and doesn't make sense).

I didnt go thru the entire thing, but I suppose I haven't missed the answer to the initial question.

-cf
 
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  • #102
Physicsguru said:
If, after time amount of time \Delta t has elapsed according to some clock which is permanently at rest in S, the photon has coordinates (L,0,0) in frame S, what is my x` coordinate in frame S`?
Guru

I think here the key is not the x' coordinate, but the t' coordinate. The light will move with the speed 'c' in the S' reference frame also, as the light speed is constant. But the time coordiante will stand still at 0. As no time will be elaspsed inspite of the fact the photon travels so fast, the photon will still be at the origin of S' frame as measured from S' frame.

The lorentz transformation becomes indefinite when when v/c goes to 1 if we do mere substitution,but I feel if we are able to take limits of the lorentz transformation as v/c goes to 1, through rules similar to L'Hospitals, it would be possible to find the t' and x' coordinates of the photon as limits and my guess is it will be equal to 0 and 0 resply always and in a way doesn't depend on t and x.

Also the location of the origin of S' reference frame measured in S reference frame will be moving at the speed of ct.

I haven't dwelled on any quantum reasoning here and I am sticking to classical physics.
 
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