Harmonic Motion: Calculating Speed in Simple Harmonic Motion

AI Thread Summary
To calculate the speed of the rider when leaving the saddle of a mechanical bull in simple harmonic motion, one must first determine the upward force at the point of ejection, where it equals the gravitational force. The relevant equations include F=ma and F=mg, along with the relationship a=w²y. Using these, the rider's velocity can be derived from the energy equation: 1/2kA² = 1/2mv² + 1/2ky². This approach provides a structured method for solving the problem effectively.
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Homework Statement



While visiting friends at Cal State Chico, you pay a visit to the Crazy Horse Saloon. This fine establishment features a 200- kg mechanical bucking bull that has a mechanism that makes it move vertically in simple harmonic motion. Whether the “bull” has a rider or not, it moves with the same amplitude 2.70 m and frequency 0.342 Hz. Being from Texas you decide to ride it the “macho” way by NOT holding on. To no ones surprise you go flying out of the saddle. While waiting for your bruises and pride to heal, you decide to calculate how fast upward you were moving when you left the saddle.

Give your answer in m/s to the second decimal place.

Homework Equations



I do not even know where to start on this one any help would greatly be appreciated

The Attempt at a Solution



same as above
 
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You have to determine the y-position at which you fly off the saddle. When does the force pushing you up (due to simple harmonic motion) equal the force of gravity?

Hint: use F=ma and F=mg. You'll need to use the fact that a=w^2y.

When you have this, you can find your velocity using the energy equation:
1/2kA^2 = 1/2mv^2 + 1/2ky^2

Does this help?
 
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