Having some issues deriving internal force functions for a section.

AI Thread Summary
A 13-foot beam is supported by a pin at x = 0 feet and a roller at x = 9 feet, with a triangular distributed load of 50 lb/ft from 0 to 9 feet and a counter-clockwise moment of 200 lb-ft at the end. The vertical forces at the pin and roller are calculated as 52.78 lbs and 172.22 lbs, respectively. The shear and bending moment equations for the section from 0 to 9 feet appear correct, but issues arise in the bending moment equation for the section from 9 to 13 feet, particularly with the term (x-3). The discussion highlights confusion over the bending moment calculation, especially since there should be zero shear after 9 feet, indicating the bending moment should remain at -200 lb-ft. The user expresses frustration over the calculations and seeks clarification on their approach.
Bill Nye Tho
Messages
48
Reaction score
0

Homework Statement



I have a 13 foot long beam supported by a pin at x = 0 feet and a roller at x = 9 feet.

There is a triangular distributed load of 50 lb/ft from 0 ft to 9 ft. (Increasing as it approaches 9 ft)

At the end of the beam there is a moment of 200 lb-ft counter-clockwise.

Homework Equations



ƩFx = 0
ƩFy=0
ƩMr = 200 lb-ft

Vertical Force at Pin: 52.78 lbs upward
Vertical Force at Roller: 172.22 lbs upward
Normal Force = 0

The Attempt at a Solution



For the first section, it seems my equations are correct;

0 < x < 9:

Shear: -.5(50/9)x^2 + 52.78
Bending: -.5(50/9)x^3/3 + 52.78x----

This is where I'm having an issue with my Bending equation;

9 < x < 13:

Shear: -225 + 52.78 + 172.22
Bending: 52.78x + 172.22(x-9) - 225(x-3)-----At exactly 9 feet, both bending functions should give a bending moment of -200 lb-ft but for some reason, I can't seem to get that answer with the second one. I tried to rework this function a few times but it's not happening.
 
Physics news on Phys.org
The applied couple (200 ft-lb) at the end of the beam (x = 13 ft) means there is a jump in the bending moment value at this location. However, for x > 9, there is zero shear. In your equations above, it's not clear what the factor (x-3) means, since the beam is 13 feet long and the right support occurs at x = 9 ft.
 
SteamKing said:
The applied couple (200 ft-lb) at the end of the beam (x = 13 ft) means there is a jump in the bending moment value at this location. However, for x > 9, there is zero shear. In your equations above, it's not clear what the factor (x-3) means, since the beam is 13 feet long and the right support occurs at x = 9 ft.

(x-3) is the distance of the resultant force (225 lbs) from the distributed load at any given point between 9 and 13 feet. <---- I think this is my problem. It makes no sense.

Since there is 0 shear after 9 feet, I'm just getting that the bending moment should be -200 lb-ft from 9 feet to 13 feet. This equation is not reflecting that though and I'm trying to figure out where I made my mistake. :(
 
Last edited:
I think I got it... I need some sleep

Bending Function: 52.78x + 172.22(x-9) - 225(x/3)
 
No ... I don't know what you mean by 225(x/3).

Also, what is 13 - 9 = ?
 
SteamKing said:
No ... I don't know what you mean by 225(x/3).

Also, what is 13 - 9 = ?

4, I can't believe I botched that up.
 
When you first calculated the reaction forces, did you check them by (say) taking moments about some axis not already used? You should show us all your working.
 
Back
Top