Having trouble with the follow problem.

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Homework Statement


differentiate: y = [-sqrt((x^2)+1]/(x) + ln(x+sqrt((x^2)+1)


Homework Equations


Chain rule, Power Rule, Derivative of a Logarithm.

The Attempt at a Solution


I've tried this a couple times, and the expression gets pretty large when I expand both terms. After I differentiate, my expression is [-1((1/2)[(x^2)+1]^-1/2 * 2x * 2x^2 - 4x[-sqrt(x^2+1)]/4x^4] +[(1/x+sqrt(x^2+1)*((1+1/2(x^2+1)^-1/2)*2x]
My apologies for the lack of clarity on either of these expressions, my LaTeX is non-existnt and grouping this without it is pretty awful. Thanks a lot in advance for anybody's help and patience.
 
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plug your equation into here:
http://www.wolframalpha.com/

then click on expand solution and it will show you exactly how to do it. Enjoy :-)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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