Head-on Collision: Calculating SUV Velocity

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In a head-on collision between a car and an SUV, the car has a mass of 1060 kg and travels at 43 m/s, while the SUV has a mass of 2550 kg and is moving in the opposite direction. The conservation of momentum equation is applied, leading to the equation 0 = (1060 kg)(43 m/s) + (2550 kg)(Vi2). After calculations, the velocity of the SUV (Vi2) is determined to be 20.26 m/s in the opposite direction, correcting the initial negative sign error. The discussion emphasizes the importance of correctly interpreting the direction of velocity in collision problems. Understanding these principles is crucial for accurately solving physics problems related to vehicle collisions.
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1. A car (mass = 1060 kg) is traveling at 43 m/s when it collides head-on with a sport utility vehicle (mass = 2550 kg) traveling in the opposite direction. In the collision, the two vehicles come to a halt. At what speed was the sport utility vehicle traveling?



2. COLM states: m1Vf1 + m2Vf2 = m1Vi1 + m2Vi2



3. Since we know the masses of the two vehicles and the initial velocity of the first car, and since the final velocities of both are zero, I plugged in the values for the variables and got the equation 0= (1060 kg)(43 m/s) + (2550 kg)(Vi2)

I did the math and got that Vi2= (1060 kg * 43 m/s)/(2550 kg) but the answer I got here, -20.26 m/s, is apparently wrong. Can someone tell me where I went wrong?
 
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your answer is 20.26 m/s in the opposite direction

not

-20.26 m/s in the opposite direction
 
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