Heat Capacity and Thermal Equilibrium

AI Thread Summary
The discussion revolves around calculating the thermal energy transfer between a 3.50-kg block of iron and a 6.25-kg block of copper as they reach thermal equilibrium. The initial temperatures are 800 K for iron and 400 K for copper. The correct approach involves using the formula for equilibrium temperature, which accounts for the differing heat capacities of the materials. The final equilibrium temperature is determined to be 558 K, indicating that the copper only increases by 158 K. The key takeaway is that the energy transfer calculation must consider the specific heat capacities and masses of both materials to find the accurate thermal equilibrium.
MaryCate22
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Homework Statement


A 3.50-kg block of iron initially at 8.00 × 10^2 K is placed on top of a 6.25-kg block of copper initially at 4.00 × 10^2 K. Assume the blocks are thermally insulated from their surroundings but not from each other and that they constitute a closed system.

How much energy is transferred thermally from the iron to the copper as the two blocks come to thermal equilibrium?

Homework Equations


heat capacity=amount of energy transferred thermally (J)/resulting change in temperature
specific heat capacity (c) =amount of energy required to raise 1 kg of a certain material by 1 degree Kelvin (J/K*kg)

c of copper is 385, c of iron is 449

The Attempt at a Solution


Thermal equilibrium would be (400+800)/2=600. So during this process the copper would be raised 200 K. Using the specific heat capacity of copper 385 J/K*kg, I found that it would be 2406.25 J to raise 6.25 kgs of it by 1 K. To Raise 200 K it would be (2406.25)(200)=481250 J.

This is incorrect, however. What am I missing?
 
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MaryCate22 said:
Thermal equilibrium would be (400+800)/2=600.
No. Any other thoughts?
 
haruspex said:
No. Any other thoughts?

They do not contribute to the equilibrium temperature equally do they? I looked up a formula for finding equilibrium temp and otherwise worked it out the same. I got the right answer, thanks!

Formula for Equilibrium Temperature: c1m1(Tf-Ti)=c2m2(Tf-Ti)

-(449)(3.5)(Tf-800)=(385)(6.25)(Tf-400) Final Temperature= 558 K, so the copper is only raised 158 degrees.
 
MaryCate22 said:
I got the right answer
Good job.
 
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