Heat flux through wall question

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SUMMARY

The discussion revolves around calculating the heat flux through a wall composed of face brick, concrete block, and an air cavity. The wall's thermal properties include a brick thickness of 10 cm, a concrete block thickness of 50 cm, and an air cavity thickness of 5 cm. The interior and exterior convection coefficients are 8.3 W/m²·K and 35 W/m²·K, respectively, with thermal conductivities of 0.79 W/m·K for brick, 1.63 W/m·K for concrete, and 0.26 W/m·K for air. To solve the problem, participants suggest assuming a unit area of 1 m² to simplify calculations for heat flux.

PREREQUISITES
  • Understanding of heat transfer principles, specifically conduction and convection.
  • Familiarity with thermal resistance calculations, including R-total.
  • Knowledge of thermal conductivity values and their application in heat transfer equations.
  • Ability to manipulate and solve equations involving temperature differences and heat flux.
NEXT STEPS
  • Learn how to calculate thermal resistance in multi-layered walls using R-total.
  • Study the concept of heat flux and its significance in building physics.
  • Explore the impact of varying convection coefficients on heat transfer rates.
  • Investigate the implications of assuming unit area in heat transfer calculations.
USEFUL FOR

Students in engineering or architecture, thermal engineers, and anyone involved in building design or energy efficiency assessments will benefit from this discussion.

Physicsswag
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Homework Statement



I was given this question.

The wall of a building is constructed of face brick (10cm thick) and concrete block (50 cm thick) with an air filled cavity (5cm thick). The interior and exterior convection coefficients are 8.3 W.m^-2.K^_1 and 35W.m^-2.K^_1 respectively. The brick thermal conductivity is 0.79W.m^-1.K^_1 , the concrete block 1.63W.m^-1.K^_1, and the air cavity 0.26W.m^-1.K^_1. If the ambient air temperature is -10 degrees celsius and the room air temperature is 21 degrees Celsius, what will be the Heat flux through the wall.

Homework Equations


I know that Rtotal is equal to 1/h-inA + L1/k1A + ... + Ln/knA + 1/h-outA (h= Heat transfer coefficient, k= thermal conductivity, L=length, A=area)

Heat transfer rate = (t1-t2)/Rtotal

Heat flux = Heat transfer rate/Area

The Attempt at a Solution


The problem is that these are all the values I was given. I wasn't given any dimensions for the wall other than the thickness so I can't Calculate the area. Is this a mistake in the question or am I supposed to do it another way?
I attempted a solution by filling in all the values given in the relevant places but had to stop when I got to the area.

Thanks
 
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Physicsswag said:

Homework Statement



I was given this question.

The wall of a building is constructed of face brick (10cm thick) and concrete block (50 cm thick) with an air filled cavity (5cm thick). The interior and exterior convection coefficients are 8.3 W.m^-2.K^_1 and 35W.m^-2.K^_1 respectively. The brick thermal conductivity is 0.79W.m^-1.K^_1 , the concrete block 1.63W.m^-1.K^_1, and the air cavity 0.26W.m^-1.K^_1. If the ambient air temperature is -10 degrees celsius and the room air temperature is 21 degrees Celsius, what will be the Heat flux through the wall.

Homework Equations


I know that Rtotal is equal to 1/h-inA + L1/k1A + ... + Ln/knA + 1/h-outA (h= Heat transfer coefficient, k= thermal conductivity, L=length, A=area)

Heat transfer rate = (t1-t2)/Rtotal

Heat flux = Heat transfer rate/Area

The Attempt at a Solution


The problem is that these are all the values I was given. I wasn't given any dimensions for the wall other than the thickness so I can't Calculate the area. Is this a mistake in the question or am I supposed to do it another way?
I attempted a solution by filling in all the values given in the relevant places but had to stop when I got to the area.

Thanks
Why don't you work the problem assuming a unit area for the wall (say 1 m2).
 
The Heat Flux is defined as the heat flow per unit area.

Chet
 

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