Heat Transfer black-body cube Problem

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To determine how many days it takes for a perfect black-body cube (0.0100 m on a side, 30 degrees C) to radiate the same energy as a 100-watt light bulb in one hour, one must apply the Stefan-Boltzmann law to calculate the power emitted per unit area. Knowing the total surface area of the cube allows for the calculation of its total power output. The energy emitted by the light bulb over one hour is 100 watt-hours, which can be converted to joules for comparison. By dividing the total energy from the light bulb by the power of the blackbody, the time required for the blackbody to emit that energy can be found. The result will likely indicate a significantly longer duration, expressed in days, due to the lower power output of the blackbody compared to the light bulb.
Marc Briancon
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How many days does it take for a perfect black-body cube (0.0100 m on a side, 30 degrees C) to radiate the same amount of energy that a one-hundred-watt light bulb uses in one hour?

If someone could point me in the right direction with how to go about solving this problem i would greatly appreciate it. I don't want to just be given the answer but shown how to go about solving this problem so that I can learn from the process. Thanks.
 
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You know the total surface area of the blackbody.

You know, from the Stefan–Boltzmann law, how much energy per unit time (power) a blackbody emits in EM radiation *per unit area.*

Therefore you know the total power of the EM radiation being emitted by this cube.

You know how much energy is emitted by the light bulb in one hour because you know its power.

Since you now know the power of the blackbody, you can calculate how much time it takes for it to radiate that amount of energy.

There you have it -- step by step.

Since the wording of the problem indicates you're expected to get an answer in days, you would expect the power of the blackbody to be much lower than that of the light bulb since it is taking such a significantly longer amount of time to radiate 100 watt-hours worth of energy.
 
Thank you so much for replying.
 
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