Heat transfer -- length of the tube required to heat water....

AI Thread Summary
The discussion revolves around calculating the length of a tube required to heat water from 20 to 40°C while maintaining the tube wall temperature at 90°C. The initial calculations provided a length of 0.0165 m, but this result was met with skepticism, as other participants calculated approximately 100 m. Key factors in the calculations include the Reynolds number, Prandtl number, Nusselt number, and heat transfer coefficient, which are essential for accurate heat transfer estimations. Participants emphasized the importance of correct algebra and assumptions in heat transfer calculations, particularly in relation to the tube's dimensions. The conversation highlights the complexity of heat transfer in short pipes and the need for thorough validation of calculations.
Ian Limjap
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Homework Statement


Water flowing at the rate 3.5 kg s−1 through a tube with an inner diameter of 2 cm is to be heated from 20 to 40◦C. If the tube wall temperature is maintained at 90◦C, determine the length of the tube required.

Homework Equations


Q'=Cp*m*(DeltaT)
Q=2*pi*r*L*Q'

The Attempt at a Solution


Q=mass flowrate*Cp(DeltaT)
=3.5*4.18*10^3*(40-20)=292600J/s
L=Q/2*pi*rQ'
However, I'm missing Q and L.
I would like to know if I need the prandlt number for this question or the viscosity of water? Would I need more information to solve this problem?
Any help will be greatly appreciated.
Thanks.
 
Last edited:
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Yes. You need to determine the Reynolds number, the Prantdl number, and then the Nussult number. You need to determine the heat transfer coefficient. Also, you sign for the heat load is wrong.

Chet
 
Thanks for replying.
 
I ended up with L=(0.023Re^0.8Pr^0.4kA(Tw-T))/q
 
Ian Limjap said:
I ended up with L=(0.023Re^0.8Pr^0.4kA(Tw-T))/q
What value did you use for T in this equation? How could the length increase with decreasing q? How could the length increase with increasing heat transfer coefficient? Is A the wetted perimeter, the cross sectional area, or the total surface area? You need to go back and get your algebra correct.

What value do you calculate for the heat load?
What values do you calculate for the Reynolds number and the Prantdl number?
What value do you calculate for the Nussult number?
What value do you calculate for the heat transfer coefficient?
What value do you calculate for the log-mean temperature difference?
What value do you calculate for the required heat transfer area?

Chet
 
Again, thanks for replying.
 
Hi, my answer is
L=0.0165m
 
I used the mean of the bulk inlet and outlet temperatures and used that to find the properties of the fluid.
 
I apologise for the confusion I wasn't really given an answer for this.
 
  • #10
Does the required heat transfer into the fluid stream really take place in just a 16,5 mm length of 20 mm bore pipe ?
 
  • #11
Re: your message in which you ask 'what do I mean ?'

Intuitively your answer seems wrong .

In any case all the assumptions and calculation methods usually used to estimate heat transfer in pipes are going to be of very doubtful validity when used on a pipe which is actually shorter than it's diameter .
 
  • #12
Ian Limjap said:
Hi, my answer is
L=0.0165m
Now let's see the answers to the questions I asked in post #5. Nidum and I are both doubtful about what you did.
 
  • #13
I got about 100m.
 
  • #14
I did my calculations again and I ended up with 100m.
 
  • #15
Ian Limjap said:
I did my calculations again and I ended up with 100m.
I still doubt that you got it right. Until you answer my questions, I won't be responding to any more of your threads. And believe me when I say that your really need help with that other heat transfer thread you started.

Chet
 
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