Help a Struggling Maths Student Solve a Quadratic Equation

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The discussion centers on solving the quadratic equation k^2 + (k + 4)^2 = 346. The confusion arises from the expansion of (k + 4)^2, which should be calculated using the FOIL method, resulting in k^2 + 8k + 16. This explains the presence of the 8k term in the equation. The correct interpretation leads to the solution of the quadratic equation, which is 11. Understanding the proper expansion technique is crucial for solving similar problems.
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I might not be the brightest bob in the bunch but I am having trouble with a simple quadratic equation.

k^2 + (k + 4)^2 = 346

According to my manual expands to:

k^2 + k^2 + 8k + 16 = 346

Everything is going fine until I see the 8k. Where did the 8k come from? Or is my manual wrong?

If anyone is willing to aid a poor soul with his maths I would be very grateful.
 
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Hmm...

k^2 + (k+4)^2 = 346

When you square k+4, please remember that it is not k^2 + 16, but rather (k+4)(k+4), which is a polynomial. After you finish using the FOIL method, you get k^2 + 4k + 4k + 16, which can be simplified to k^2 + 8k + 16, which is how you get your 8k.

The solution to the problem is 11 :smile: (Quadratic Equation).

Besides... are you in 9th grade?
 
yes

Because (k + 4) ^2 = (k+4)(k+4) and you can't just multiply k*k and add it to 4*4 you have to multiply each element as in: k*k + k*4 + k*4 +4*4 which will give you k^2 + 8k + 16. so if you had (k+ 3)(k + 2) = k^2 + 2*k + 3*k + 6
 
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