Help Calculating focal length for magnifying glass

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Homework Help Overview

The original poster seeks to determine the focal length of a magnifying glass, given its magnification of 5. They express uncertainty about how to calculate the focal length using only this information and describe their attempts to apply the magnification formula and focal length formula based on measured distances.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss various methods to find the focal length, including using sunlight, ceiling lights, and reading a newspaper. Some question the effectiveness of these methods and the influence of the eye's lens on measurements.

Discussion Status

Participants are exploring different techniques for measuring focal length and discussing the implications of eye accommodation. Some have provided guidance on practical methods, while others are questioning the assumptions behind these techniques.

Contextual Notes

There is a mention of the difficulty in measuring the radius of curvature of the lens surfaces, and the need for a bright, distant object for accurate measurements. The original poster's familiarity with the thin lens equation is noted, along with the potential for error in focusing techniques.

Stomper123
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So I bought a magnifying glass for a project and I need to find out the focal length of it in order to use it. I'm given the magnification of the converging lens, which is 5, but I don't any methods or how I could find out the focal length given only the magnification. I attempted to set distance object that I actually measured and put it into the magnification formula and then took the distance of the image and put it into the focal length formula. However, when I tested it out it didn't seem quite right. Are there anyways I could do this mathematically? If not how else could I do this?
 
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Focal length can be calculated knowing the radii of curvature of both lens surfaces. But radius of curvature is a difficult parameter to measure. If you focus the sun to a spot on paper, the distance from the centre of the lens to the burning paper is the focal length. Centre of the lens being a point inside the glass, roughly midway between the two lens surfaces.

In the absence of sun, try reading a newspaper with the lens. The distance from the page to the centre of the lens where you judge print to be sharpest is the focal length.
 
NascentOxygen said:
In the absence of sun, try reading a newspaper with the lens. The distance from the page to the centre of the lens where you judge print to be sharpest is the focal length.

Does this second method really work? I've used the sun method, and also focused ceiling lights on the floor and measured the two distances (to use the thin lens equation), but it seems like if you focus the image on your eye, your eye lens enters into things...?
 
berkeman said:
I've used the sun method, and also focused ceiling lights on the floor and measured the two distances (to use the thin lens equation),
would a lamp work?
 
Stomper123 said:
would a lamp work?

The point is that you want some bright object that is very far away, so you don't need to measure the distance to that light source. Depending on the accuracy you want for your focul distance number, you could use a streetlight across the street, probably.

Are you familiar with the thin lense formula, which relates the focul distance to the object and image distances?
 
berkeman said:
Does this second method really work? I've used the sun method, and also focused ceiling lights on the floor and measured the two distances (to use the thin lens equation), but it seems like if you focus the image on your eye, your eye lens enters into things...?

I think I see how this works now. The rays heading to your eye are parallel, so as long as you focus your eyes on infinity, the lens-newspaper distance is the focul length. Interesting (but possible to make a small error if you aren't used to focusing your eyes on infinity...) :smile:
 
Oh okay
I am familiar with the thin lense equation
Thanks! I'll try this out
 
berkeman said:
I think I see how this works now. The rays heading to your eye are parallel, so as long as you focus your eyes on infinity, the lens-newspaper distance is the focul length. Interesting (but possible to make a small error if you aren't used to focusing your eyes on infinity...) :smile:
I'm just wondering. How would you focus your eyes on infinity :O?
 
  • #10
Stomper123 said:
I'm just wondering. How would you focus your eyes on infinity :O?

As long as you are not nearsighted or farsighted, you just relax your vision. The relaxed state of your eye lens muscles let's the lens go to its thinnest shape, which focuses the eyes on infinity. That's what happens when you look a long way away at something. As you look closer, the eye lense muscles squish the lens some, which makes it thicker in the middle (higher power), to focus the closer image on the retina.

So as a practical matter with this newspaper technique, you could look past the newspaper at something a long ways away, and then try to keep that same relaxed focus as you change your gaze to the newspaper as seen through the magnifying lens.

Try several of the methods we've talked about in this thread, and see what values of focal length you get. Kind of fun experiments...:smile:
 
  • #11
berkeman said:
Does this second method really work? I've used the sun method, and also focused ceiling lights on the floor and measured the two distances (to use the thin lens equation), but it seems like if you focus the image on your eye, your eye lens enters into things...?
If you hold the lens against your eye like a monocle then it probably won't work. But the right way to use a magnifying glass is to hold it away from you at a distance well beyond focal length, so the rays leaving it are parallel. Then it doesn't make any difference whether you move your eyes nearer to, or further back from, the lens, the image remains in focus.

I think that's how it works, anyway. :smile:
 

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