HELP columbs law/charges 2 charges on a line, looking for

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To find the net electric field at specific points on the x-axis due to two charges, use Coulomb's law and the electric field formula E = k*q/r^2. At x = 0 cm, the positive charge (+7.7 µC) contributes to the field pointing right, while the negative charge (-22 µC) contributes to the field pointing left. At x = +5.9 cm, both charges influence the electric field, with the direction determined by their signs. The net electric field is the vector sum of the fields from both charges at each point. Understanding the contributions and directions of each charge is essential for solving the problem accurately.
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Homework Statement


Two charges are placed on the x axis. One of the charges (q1 = +7.7 µC) is at x1 = +2.9 cm and the other (q2 = -22 µC) is at x2 = +9.2 cm.
(a) Find the net electric field (magnitude and direction) at x = 0 cm. (Use the sign of your answer to indicate the direction along the x-axis.)
(b) Find the net electric field (magnitude and direction) at x = +5.9 cm. (Use the sign of your answer to indicate the direction along the x-axis.)


Homework Equations



Columbs law, F=K*(|q1|*|q2|)/r2

The Attempt at a Solution



I'm fairly lost as to how to start this. I know that to figure out the force of the two charges acting on one another you would use the equation above with r being the distance between the two charges. What I don't know is how to figure out the charge on a spot where there is no charge previously. I think that it would be only the positive charge acting on the spot since (field wise) it is the only one that actually goes anywhere near the point. Or am I totally off? Help?
 
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The formula for electric field is
E = k*q/r^2.
The direction of field depends on the sign of the charge. It is away from the positive charge and towards the negative charge.
 
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