Help critique my problem solving and thinking process (problem included)

AI Thread Summary
The discussion centers on improving problem-solving skills in physics, particularly in tackling textbook questions that require a mathematical approach rather than conceptual understanding. The original poster struggles with setting up equations involving multiple unknowns, specifically in a mechanics problem related to a climber's static friction and tension. Key advice includes resolving forces in both x and y directions and taking moments about strategic points to simplify the equations. The importance of identifying relationships between forces to eliminate unknowns is emphasized, suggesting that a deeper engagement with the problem may lead to clearer insights. Overall, the conversation highlights the necessity of mastering algebraic techniques alongside conceptual knowledge in physics problem-solving.
ryley
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Homework Statement
I'm having difficulty seeing how to take math and apply it to the situation. Or recognizing when I can use a technique.
Relevant Equations
Fnetx=0
Fnety=0
Fnetz=0
Hello all, thanks for reading my post! I'm posting as I need help with my problem solving and thinking approach. For the most part I can figure out how to set up the problem and what I need to find, but my problem lies in textbook questions that rely more on seeing a more math based approach to solving rather than thinking about the concepts. What I mean is, the concepts are easy to see but minimal information is given leaving multiple variables and so methods like substitution are needed as well as other algebraic techniques. I'll post a question that this applies to and show my thinking process as well as a diagram. If anyone is able to help me identify what exactly it is I'm doing wrong so as to help me determine a solution to a problem it would be greatly appreciated.

Question

A climber with a weight of 533.8 N is held by a belay rope connected to her climbing harness and belay device; the force of the rope on her has a line of action through her center of mass. The indicated angles are 30 degrees(top) and 40 degrees(bottom). If her feet are on the verge of slipping on the vertical wall, what is the coefficient of static friction between her climbing shoes and the wall?

First thoughts
- I will need to sum the forces in x and y directions as well as torques.
- doing this yields a few unknowns and I can't seem to see a way to solve for one and sub it in or equate any of them.
- I think It will be best to use her foot contacting the wall as the origin to eliminate the Fs and FN from the torque equations, but that still leaves me with tension as an unknown.
- The force net equations also have unknowns that I can't see a way to solve for.

This Is where I get stuck and can't see a way to solve for what I need as its not about applying concepts anymore instead it is more math. The solution shows to use some substitution as well as equating two equations, this isn't the hard part to solve as I can do the algebra but its seeing that, that is what I'm suppose to do that I'm having trouble realizing.

I'll attach a picture of the diagram as well as the solution.

Thanks for any help!
 

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Thanks for some help! For the coefficient I'd need in this case the Normal force of her shoes on the wall to solve for Fs and I think tension in order to solve one of the equations that has one of the unknowns I need for the friction coefficient. I see the components I need, like Fs FN and Tension but how to set up equations to solve I don't see.
 
ryley said:
Hello all, thanks for reading my post! I'm posting as I need help with my problem solving and thinking approach. For the most part I can figure out how to set up the problem and what I need to find, but my problem lies in textbook questions that rely more on seeing a more math based approach to solving rather than thinking about the concepts.

So a general mantra for these simpler mechanics problems is "Resolve, Resolve, take Moments". The first step is to get these equations. You can resolve in x, resolve in y, and take moments about an appropriate point. Note that a system of three equations can let you solve three unknowns, not more.

ryley said:
- I think It will be best to use her foot contacting the wall as the origin to eliminate the Fs and FN from the torque equations, but that still leaves me with tension as an unknown.

Good thinking. Yes, that leaves you with an unknown, but can you solve for it? Write out the moment equation and see if you can solve for tension. (HINT: you can)

You have also highlighted another good tip- resolve at a point where you can get rid of lots of forces. We want to make it easy for us to solve, so we want as few variables as possible.

This problem doesn't require much algebra when you write out the equations.

Hope that is of some help.
 
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Master1022 said:
So a general mantra for these simpler mechanics problems is "Resolve, Resolve, take Moments". The first step is to get these equations. You can resolve in x, resolve in y, and take moments about an appropriate point. Note that a system of three equations can let you solve three unknowns, not more.
Good thinking. Yes, that leaves you with an unknown, but can you solve for it? Write out the moment equation and see if you can solve for tension. (HINT: you can)

You have also highlighted another good tip- resolve at a point where you can get rid of lots of forces. We want to make it easy for us to solve, so we want as few variables as possible.

This problem doesn't require much algebra when you write out the equations.

Hope that is of some help.
Thanks for the help, I think I need to stick with the problem a bit longer, the solution just seemed to use a lot of techniques that don't dawn on my immediately, so maybe sticking with it for a little longer will help me to see clearer a way to solve.
 
ryley said:
It will be best to use her foot contacting the wall as the origin to eliminate the Fs and FN from the torque equations,
That can be best, but not here. You need the relationship between those two forces in order to find the coefficient. What you would rather not have to care about is the tension. What does that suggest for an axis?
 
haruspex said:
That can be best, but not here. You need the relationship between those two forces in order to find the coefficient. What you would rather not have to care about is the tension. What does that suggest for an axis?
Interesting, okay so you are asking which point should I use as the pivot to eliminate tension? if that's the case then I would think using the climbers center of mass as that would be where tension would have a moment arm of zero. Thanks!
 
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I looked at the solution you posted. Note that ##\cos(90- x) = \sin x## and ##\sin(180 - x) = \sin x##.
 
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