- #1
hungryhippo
- 10
- 0
Homework Statement
given a function defined by
f(x,y) {= |xy|^a /(x^2+y^2-xy), if (x,y) cannot be (0,0)
and = 0, if (x,y) = (0,0)
Find all values of the real number a such that f is continuous everywhere
e= epsilon
d= delta
In order to prove this, I know I need to do an epsilon delta proof for a limit. I know that,
|(x1,x2)-(y1,y2)| < d
|x1-y1, x2-y2| < d
sqrt ( (x1-y1)^2+(x2-y2)^2 ) < d
since we know, that for one (x,y) = (0,0) the above is just
sqrt(x^2+y^2) < d
also, assuming e<0
we have
|f(x,y)-f(xo,yo)|< e
saying that f(xo,yo) corresponds to when xo = 0 and yo =0, we have
|f(x,y)|< e
||xy|^a /(x^2+y^2-xy)| < e
From here on, I don't know which path to take...I don't have any background on delta epsilon and this is my first time seeing it. So i'd really appreaciate your help
Thanks in advance :)