Help fast exam soon, question about XOR.Boolean algebra

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Can Xor be distributive for all cases ?

ex,


(X xor Y)Z

=

XZ xor YZ in all cases?
 
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Remembering that

A\oplus B = \overline A B + A\overline B

what do you get for both sides of your (hoped for) equality? It's easy...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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