Help finding kg of mercury please

Thread starter wmsnyder
Start date Sep 16, 2009
Tags

Mercury

AI Thread Summary

To determine how many kilograms of mercury are needed to fill a 250ml container, the density of mercury is essential. The correct density of mercury is 13,534 kg/m^3, not 0.0136 kg/m^3. Using the relationship between density, mass, and volume, the mass can be calculated by multiplying the volume by the density. Therefore, the mass of mercury required for the container can be accurately calculated using the correct density value. Understanding these concepts is crucial for solving the problem effectively.

Sep 16, 2009

wmsnyder

Homework Statement

How many kg of mercury to fill a 250ml container?

Homework Equations

The Attempt at a Solution

Physics news on Phys.org

Sep 16, 2009

Anden

You need the density.

Sep 16, 2009

wmsnyder

.0136 kg/m^3 Is that what you mean?

Sep 16, 2009

Anden

Yes, use the definition of density (kg / m^3) to get a relationship between density, mass and volume.

Oh, and the value of density is wrong, you must multiply it by 10^6 to get it in kg / m^3

Sep 16, 2009

Kalvarin

It's 13534 Kg/m^3

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »