- #1
jog511
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Homework Statement
lim x->0 sinxcosx/x
Homework Equations
lim x->0 sinx/x = 1
The Attempt at a Solution
Pretty sure I need to use above property but I believe cosx/x is undef.
jog511 said:Homework Statement
lim x->0 sinxcosx/x
Homework Equations
lim x->0 sinx/x = 1
The Attempt at a Solution
Pretty sure I need to use above property but I believe cosx/x is undef.
The limit of sinxcosx/x as x approaches 0 is equal to 1. This can be solved using the squeeze theorem or by simplifying the expression using trigonometric identities.
To evaluate the limit of sinxcosx/x, you can use L'Hopital's rule or trigonometric identities such as the double angle formula for cosine. You can also graph the function to better understand its behavior.
Yes, you can use the limit of sinxcosx/x to find the derivative of sinx. By taking the limit as x approaches 0, you will get the derivative of sinx, which is cosx.
The limit of sinxcosx/x is equal to 1, while the limit of sinx/x does not have a value as it approaches infinity. This is because as x gets larger, the value of sinx oscillates between -1 and 1, resulting in an undefined limit.
Yes, you can use the limit of sinxcosx/x to solve other trigonometric limits. This is because it is a fundamental limit that can be used to derive other limits, such as the limit of tanx/x. Additionally, it can be used in conjunction with other trigonometric identities to solve more complex limits.