- #1
buffgilville
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A bullet of mass 0.11 kg and moving along the horizontal direction with a speed 1129.8 meters/sec hits a wooden block of mass 12.7 kg and gets embedded in it. Find the impulse acting on the block in meters/sec.
Here's what I did:
initial momentum = (0.11*1129.8) + (12.7*0) = 124.278
final momentum = (0.11 + 12.7) v
inelastic collision, momentum is conserved; so:
initial momentum = final momentum
124.278 = 12.81v
v = 9.702 m/s
final momentum = (12.81*9.702) = 124.278
Impulse = final momentum - initial momentum
= (124.278-124.278)
= 0
The answer is 123.21 meter/sec. What did I do wrong? Please help. Thanks!
Here's what I did:
initial momentum = (0.11*1129.8) + (12.7*0) = 124.278
final momentum = (0.11 + 12.7) v
inelastic collision, momentum is conserved; so:
initial momentum = final momentum
124.278 = 12.81v
v = 9.702 m/s
final momentum = (12.81*9.702) = 124.278
Impulse = final momentum - initial momentum
= (124.278-124.278)
= 0
The answer is 123.21 meter/sec. What did I do wrong? Please help. Thanks!