A bullet of mass 0.11 kg and moving along the horizontal direction with a speed 1129.8 meters/sec hits a wooden block of mass 12.7 kg and gets embedded in it. Find the impulse acting on the block in meters/sec. Here's what I did: initial momentum = (0.11*1129.8) + (12.7*0) = 124.278 final momentum = (0.11 + 12.7) v inelastic collision, momentum is conserved; so: initial momentum = final momentum 124.278 = 12.81v v = 9.702 m/s final momentum = (12.81*9.702) = 124.278 Impulse = final momentum - initial momentum = (124.278-124.278) = 0 The answer is 123.21 meter/sec. What did I do wrong? Please help. Thanks!