Help in The Oxidation Number Method ?

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The discussion revolves around the confusion in balancing redox reactions using the Oxidation Number Method, specifically with the equation Cu + HNO3 = Cu(NO3)2 + NO2 + H2O. The user initially balances the electrons lost and gained, resulting in Cu + 2HNO3 = Cu(NO3)2 + 2NO2 + H2O. However, they later adjust the equation to Cu + 4HNO3 = Cu(NO3)2 + 2NO2 + 2H2O, raising concerns about whether this adjustment disrupts the balance of charges. The suggestion is made to first balance the net ionic reaction to clarify the balancing process. Ultimately, the user seeks confirmation on whether their final equation remains balanced.
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Help in "The Oxidation Number Method"?

Homework Statement



I just learned how to balance the redox reactions with this method, but there is something I don't understand ...
Look at this example :
Cu+HNO3 = Cu(NO3)2+NO2+H2O
after making the number of electrons gained and lost equal we get this equation :
Cu+2HNO3 = Cu(NO3)2+2NO2+H2O
Now the number of electrons gained and lost is the same but we must continue balancing the equation and so we get at last :
Cu+4HNO3 = Cu(NO3)2+2NO2+2H2O
Didn't we just ruin the equation again ? ( the number of electrons lost and gained isn't the same ) Or am I wrong ?
Someone explain please

Homework Equations



Cu+HNO3 = Cu(NO3)2+NO2+H2O
 
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Please elaborate on what you are doing, step by step.

My guess is that you should try to balance net ionic reaction first, and it will become obvious what the problem is (or rather - why there is no problem). But I can be wrong, hard to say without details.
 
Borek said:
Please elaborate on what you are doing, step by step.

My guess is that you should try to balance net ionic reaction first, and it will become obvious what the problem is (or rather - why there is no problem). But I can be wrong, hard to say without details.

Ok here is the original equation :
Cu+HNO3 = Cu(NO3)2+NO2+H2O

Now according to "The Oxidation Number Method", I must balance the charges first
and if you look at the equation you will find that :
Cu -> lost 2electrons
N -> gained 1electron

Then balance the charges by multiplying N by 2, so I multiplied HNO3 on the reactant side and multiplied NO2 on the product side
The equation now should be like this :
Cu+2HNO3 = Cu(NO3)2 + 2NO2 + H2O

Now charges are balanced, but the equation isn't, and to do this we should make a little change, it will become like this :
Cu+4HNO3 = Cu(NO3)2 + 2NO2 + 2H2O

Now the equation is fully balanced but we multiplied 2HNO3 again and it became 4HNO3 ...
My question is didn't we - by doing that - unbalanced the charges again ?
Hope I made it clear enough
Thanks.
 
As I signaled earlier - balance net ionic reaction first.
 
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