Help -interpreting- this topology question, no actual work required

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Homework Statement



Show that the set S ⊆ C[0, 1] consisting of continuous functions which map Q to Q is dense, where the metric on C[0, 1] is defined by d(f,g) = max |f(x)−g(x)|.

All else I need to know is what the question doesn't mention - what the set is dense in? I assume it doesn't mean dense in itself since it probably wouldn't bother giving a specific space then, so do you think it means the set of continuous R->R functions on [0,1] or all R->R functions on [0,1], or what? Just need to actually understand what it means before I can get going - thanks!
 
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I'm sure they mean dense in C[0,1], the set of all continuous functions from [0,1]->R.
 
Dick said:
I'm sure they mean dense in C[0,1], the set of all continuous functions from [0,1]->R.

Once again Dick, thanks for all the help, you're a lifesaver!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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