Help me out with this physics problem

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To calculate the spacing between the uprights of the iron railing based on the sound frequency of 640 Hz, the wavelength can be determined using the formula λ = v/f, where v is the speed of sound (330 m/s). The sharp sound produced by the man creates echoes off the bars, which contribute to the perceived frequency. The round trip time of the sound must be considered in the calculation. It is advisable to clarify assumptions in the answer to ensure credit is received, even if the interpretation of the problem differs from the instructor's intent.
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I have been scratching my head all night about this problem...

A man standing close to an iron railing consisting of evenly-spaced uprights makes a sharp sound and hears a note of frequency 640hz. calculate the spacing between the uprights. (speed of sound in air = 330m/s)


perhaps one of you can help me out with this problem...


THANKS!
 
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It is not clear to me that there is any relationship between the bars and the sound. But

\lambda = \frac v f
where
\lambda= {Wavelength}
v= {velocity}
f = {frequency}

Is what you need.
 
Integral said:
It is not clear to me that there is any relationship between the bars and the sound. But

\lambda = \frac v f
where
\lambda= {Wavelength}
v= {velocity}
f = {frequency}

Is what you need.

I get the problem. The sharp sound is a single discrete narrow pulse, and it echos of the bars, one after another, so that it's total return to the observer has the given frequency.

To solve this problem, there is one more bit of information you'll need to know, and that's the speed of sound, which if I recall is about 770 mph at STP (convert that to m/s). Use that for v to get the bar spacing. Don't forget it's round trip time you'll be working with.

I'm not 100% certain this is what the problem intends, so maybe you should desribe your assumptions in the answer to the homework problem. This way you can get credit even if the instructor intended something else.
 
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