Help me, to understand kirchoff's voltage law.

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Discussion Overview

The discussion revolves around the application of Kirchhoff's Voltage Law (KVL) to a circuit diagram created by the original poster. Participants explore the assumptions regarding current direction and the implications of having a single branch in the circuit.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • The original poster questions the choice of current direction, specifically whether to represent the combined current as (I1 + I2) in the circuit diagram.
  • Some participants assert that the circuit only has one branch, implying that the current is uniform throughout.
  • There is a proposed equation based on KVL: -I1R1 + E2 - I1R2 + E1 = 0, which is reiterated by multiple participants.

Areas of Agreement / Disagreement

Participants generally agree on the uniformity of current in the single branch of the circuit, but there is uncertainty regarding the original poster's choice of current representation.

Contextual Notes

The discussion does not resolve the original poster's concerns about the current direction and its representation, leaving some assumptions and interpretations open to further clarification.

sphyics
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N.B: I was trying to apply kirchoff’s voltage law to this ckt diagram. (created by myself :smile:)


recreated.jpg



To apply kirchoff’s voltage law:

1) Assume current along with their directions in each branch of the ckt.
(Assumed: and represented by arrows (red for I1 and violet for (I1 + I2) tis is wer my problem, am I right in choosing the violet arrow as (I1 + I2). Intuitively I am not convinced by my choice.
 
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Your circuit only has one "branch". The current is the same throughout.
 
Doc Al said:
Your circuit only has one "branch". The current is the same throughout.

agree with the point; so the equation would be:

-I1R1 + E2 - I1R2 + E1 = 0
 
sphyics said:
agree with the point; so the equation would be:

-I1R1 + E2 - I1R2 + E1 = 0
Right.
 
Thank you Doc Al :smile:
 

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