Help Me Two Blocks Connected by a Cord

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Two blocks, A and B, are connected by a cord over a frictionless pulley, with A on a horizontal surface and B on a ramp. Block A has a mass of 40 kg and block B has a mass of 120 kg, with a coefficient of kinetic friction of 0.20 for both blocks. The discussion centers on calculating the acceleration of the blocks and the tension in the cord as they begin to move. It is clarified that the acceleration of both blocks must be assumed equal until block B hits the barrier, as any difference would cause the cord to slacken. The conversation emphasizes the importance of drawing free body diagrams for both masses to analyze the forces acting on them.
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Mechanics help :(!

I REALLY NEED HELP :(
Two blocks are connected by a cord which passes over a frictionless pulley at D.
Block A has a mass of 40 kg and block B a
mass of 120 kg. A rests on a horizontal
surface, while B rests on a ramp with the slope
shown. B is initially in a position 3 m from the
stop C as shown. The coefficient of kinetic
friction between the blocks and the surface
beneath is μK = 0.20 for both A and B.

(a) Find the acceleration of the two blocks and
the tension T in the cord, assuming that the
blocks just begin to move at time t = 0.
 
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Diagram?
 


First we draw the FBD for mass A and for mass B.

How many forces act on each?
 


on mass 1 we have forcetension - forcefriction + m*g = ma
mass2 -frocetension-Forcefriction2+(m*g)sin theta= m2a

the thing that's confusing me is if we could have assumed that the aceleration of B is same as acceleration of a before it hits the barrier in the diagram
 


awesome4444 said:
on mass 1 we have forcetension - forcefriction + m*g = ma
mass2 -frocetension-Forcefriction2+(m*g)sin theta= m2a

the thing that's confusing me is if we could have assumed that the aceleration of B is same as acceleration of a before it hits the barrier in the diagram

To avoid confusion, instead of mass 1 let us call it mass A as in diagram.

Re 1st equation: I do not know why you have m*g.

Until mass B hits the barrier at C we HAVE TO assume that the acceleration of B is the same (in magnitude) as that of A because otherwise the string either snaps or becomes slack and so there would not be any tension at all!
 
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