Will a Rock Thrown Upward Reach the Top of a Castle Wall?

[BeckyStar678]

Homework Statement

an attacker at the base of a castle wall 3.65 m high throws a rock straight up with the speed 7.40 m/s at a height of 1.55 m above the ground. a.) will the rock reach the top of the wall? b.) if so, what is its speed at the top? if not, what initial speed must it have to reach the top? c.) find the change in speed of a rock thrown straight down from the top of the wall at an inital speed of 7.40 m/s and moving between the same two points. d.) does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward b/t the same elevations? explain physically why it does or does not agree

Homework Equations

xf=xi+ vxit+1/2axt2

The Attempt at a Solution

so for the first question, what i did was plug in the data for the above equation (making acceleration -9.80) and getting the time which is 9 seconds. so i took that as yes it does reach the top after 9 seconds, because i put xf as 3.65. so then i took the 9 seconds and plugged it in the equation and got 2.4 as the speed at the top. and then i don't know what to do for c.

 

[alphysicist]

Hi BeckyStar678,

Homework Statement

an attacker at the base of a castle wall 3.65 m high throws a rock straight up with the speed 7.40 m/s at a height of 1.55 m above the ground. a.) will the rock reach the top of the wall? b.) if so, what is its speed at the top? if not, what initial speed must it have to reach the top? c.) find the change in speed of a rock thrown straight down from the top of the wall at an inital speed of 7.40 m/s and moving between the same two points. d.) does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward b/t the same elevations? explain physically why it does or does not agree

Homework Equations

xf=xi+ vxit+1/2axt2

The Attempt at a Solution

so for the first question, what i did was plug in the data for the above equation (making acceleration -9.80) and getting the time which is 9 seconds.

I don't believe this is correct; can you show how you got this result (what numbers you used and how you used them in the equation).