Help : Perpendicular distance of the plane

AI Thread Summary
To find the perpendicular distance from the origin to the plane defined by the equation 5x + 2y - z = -22, set x and y to zero to solve for z, which gives the intersection point. The perpendicular distance is the absolute value of the z-coordinate at this point. Alternatively, using Lagrange Multipliers can help find the coordinates of the point on the plane that minimizes the distance from the origin. By identifying the normal vector from the plane's equation, one can create a parametric equation for a line through the origin that intersects the plane. This approach effectively determines the required perpendicular distance.
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Homework Statement


Find the perpendicular distance of the plane 5x+2y-z=-22 from the origin O by first finding the co-ordinates of the point P on the plane such that OP is perpendicular to the given plane.


Homework Equations


It only given plane vector,how i going to figure out the perpendicular distance?



The Attempt at a Solution


I really don't know where to start.Can help to elaborate?

Thanks
 
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Set x and y equal to zero, solve for z. The perpendicular distance will be the absolute value of this number.
 
sandy.bridge said:
Set x and y equal to zero, solve for z. The perpendicular distance will be the absolute value of this number.


You mean (X,Y.Z) = (0.0.Z)?Then minus the plane location?
 
One option is to use Lagrange Multipliers to get the coordinates of the point by treating it as a minimization problem (i.e. distance from origin to an arbitrary point) with the constraint that the arbitrary point must lie on the plane. Hint: minimizing the square of the distance also minimizes the distance.
 
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You should be able to write a normal to the plane by inspection of the defining equation. Any line that is perpendicular to the plane must be parallel to this normal. So write a parametric equation of a line that passes through the origin that lies along this normal vector. Where does this line intersect the plane?
 
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