Help : Perpendicular distance of the plane

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Homework Help Overview

The problem involves finding the perpendicular distance from the origin to a given plane defined by the equation 5x+2y-z=-22. The original poster expresses uncertainty about how to approach the problem, particularly in determining the coordinates of a point on the plane that would allow for this distance to be calculated.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest setting x and y to zero to solve for z, while others question the implications of this approach. There is also a mention of using Lagrange Multipliers to minimize the distance from the origin to a point on the plane, treating it as a constrained optimization problem. Additionally, one participant discusses the concept of a normal vector to the plane and its relevance to finding the intersection with a line from the origin.

Discussion Status

The discussion is active, with various approaches being explored, including direct substitution and optimization techniques. Participants are engaging with each other's ideas, and some guidance has been offered regarding the use of normal vectors and parametric equations. However, there is no explicit consensus on a single method to solve the problem.

Contextual Notes

The original poster indicates a lack of clarity on how to begin the problem, and there may be assumptions regarding the methods available for calculating distances in three-dimensional space that are being questioned.

ahgang
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Homework Statement


Find the perpendicular distance of the plane 5x+2y-z=-22 from the origin O by first finding the co-ordinates of the point P on the plane such that OP is perpendicular to the given plane.


Homework Equations


It only given plane vector,how i going to figure out the perpendicular distance?



The Attempt at a Solution


I really don't know where to start.Can help to elaborate?

Thanks
 
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Set x and y equal to zero, solve for z. The perpendicular distance will be the absolute value of this number.
 
sandy.bridge said:
Set x and y equal to zero, solve for z. The perpendicular distance will be the absolute value of this number.


You mean (X,Y.Z) = (0.0.Z)?Then minus the plane location?
 
One option is to use Lagrange Multipliers to get the coordinates of the point by treating it as a minimization problem (i.e. distance from origin to an arbitrary point) with the constraint that the arbitrary point must lie on the plane. Hint: minimizing the square of the distance also minimizes the distance.
 
Last edited:
You should be able to write a normal to the plane by inspection of the defining equation. Any line that is perpendicular to the plane must be parallel to this normal. So write a parametric equation of a line that passes through the origin that lies along this normal vector. Where does this line intersect the plane?
 

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