Help Separable Differential Equation Problem

In summary: M + ASubstituting this into the second equation, we get:14 = 72/6 + A*e^-ln(1/6)14 = 12 + A/6Multiplying both sides by 6, we get:84 = 12 + ASubtracting 12 from both sides, we get:72 = ANow we can plug this value of A back into our equation for P(t) to solve for M:12 = M + 72*e^-kSubstituting our value of k from earlier, we get:12 = M + 72*(1/6)12 = M + 12
  • #1
HypeBeast23
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Homework Statement



Problem:

(1 pt) Let P(t) be the performance level of someone learning a skill as a function of the training time t. The derivative \displaystyle \frac{dP}{dt} represents the rate at which performance improves. If M is the maximum level of performance of which the learner is capable, then a model for learning is given by the differential equation

\frac{dP}{dt} = k(M-P(t))

where k is a positive constant.
Two new workers, Mark and Peter, were hired for an assembly line. Mark could process 12 units per minute after one hour and 14 units per minute after two hours. Peter could process 10 units per minute after one hour and 15 units per minute after two hours. Using the above model and assuming that P(0)=0, estimate the maximum number of units per minute that each worker is capable of processing.


Homework Equations



Method of solving separable differential equations, basic integration...

The Attempt at a Solution



I have solved up to the equation for P(t) = M + A*e^-kt (where A represents +/- e^c), and found that the limit of P(t) as t approaches infinity is M. After that, I don't know how to find the maximum number of units per minute for each of Mark and Peter. Any help would be appreciated. Thanks!
 
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  • #2


I would first like to commend you for using a mathematical model to solve this problem. It shows a strong understanding of the concept and will lead to a more accurate solution.

To find the maximum number of units per minute for each worker, we can use the information given in the problem. We know that after one hour, Mark can process 12 units per minute, and after two hours, he can process 14 units per minute. This means that after two hours, Mark's performance level, P(2), is equal to 14. We can plug this into our equation for P(t) to solve for the constant M:

14 = M + A*e^-2k

Next, we can use the information for Peter to set up a similar equation:

15 = M + A*e^-2k

Subtracting the two equations, we can eliminate the constant A and solve for M:

14 - 15 = M + A*e^-2k - (M + A*e^-2k)

-1 = 0

This means that M, the maximum performance level, is equal to -1, which doesn't make sense in this context. This could be due to an error in the given information or in the model itself.

Alternatively, we can use the given information to set up a system of equations and solve for M and k simultaneously. Using the first equation (P(1) = 12), we get:

12 = M + A*e^-k

And using the second equation (P(2) = 14), we get:

14 = M + A*e^-2k

Solving for A in the first equation and substituting into the second equation, we get:

14 = M + 12*e^-k*e^-k

14 = M + 12*e^-2k

Subtracting the two equations, we get:

2 = 12*e^-2k

Solving for e^-2k, we get:

e^-2k = 1/6

Taking the natural log of both sides, we get:

-2k = ln(1/6)

k = -ln(1/6)/2

Now we can plug this value of k back into one of the original equations to solve for M:

12 = M + A*e^-(ln(1/6))

12 = M + A*(1/6)

12 = M + A/6

Multiplying
 

1. What is a separable differential equation?

A separable differential equation is a type of differential equation where the variables can be separated into two separate functions, one representing the dependent variable and the other representing the independent variable. This allows for the equation to be solved by integrating both sides of the equation separately.

2. How do I know if an equation is separable?

An equation is separable if it can be written in the form of dy/dx = f(x)g(y). If both functions, f(x) and g(y), can be integrated separately, then the equation is separable.

3. What are the steps for solving a separable differential equation?

The steps for solving a separable differential equation are as follows:

  1. Separate the variables, with all y terms on one side and all x terms on the other.
  2. Integrate both sides of the equation with respect to x and y, separately.
  3. Include a constant of integration on the side that was integrated with respect to x.
  4. Solve for y to find the general solution.
  5. If an initial condition is given, plug in the values to find the particular solution.

4. Can all differential equations be solved using separation of variables?

No, not all differential equations can be solved using separation of variables. Only equations that can be written in the form of dy/dx = f(x)g(y) can be solved using this method.

5. Are there any tips for solving difficult separable differential equations?

One tip for solving difficult separable differential equations is to try to manipulate the equation algebraically to make it easier to separate the variables. Another tip is to try using substitution to simplify the equation before separating the variables. It is also helpful to practice and become familiar with different integration techniques.

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