Help solving Conditioning problem

  • Context: MHB 
  • Thread starter Thread starter natalia
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on the numeric conditioning of the area of a triangle, represented by the formula S = 1/2 ab sin(γ). Participants analyze how errors in the variables a, b, and γ affect the calculation of S. They derive the absolute and relative error formulas, demonstrating that the relative error in S can be expressed as the contributions from each variable, particularly emphasizing the role of γ in amplifying errors for small angles.

PREREQUISITES
  • Understanding of trigonometric functions, particularly sine and cosine.
  • Familiarity with error analysis concepts, including absolute and relative errors.
  • Basic knowledge of calculus, specifically differentiation.
  • Ability to interpret mathematical formulas and symbols.
NEXT STEPS
  • Research the implications of numeric conditioning in computational geometry.
  • Learn about error propagation techniques in mathematical modeling.
  • Study the behavior of trigonometric functions for small angles.
  • Explore advanced topics in numerical analysis, such as stability and convergence.
USEFUL FOR

Mathematicians, engineers, and students involved in computational geometry or numerical analysis who are interested in understanding error propagation in geometric calculations.

natalia
Messages
6
Reaction score
0
Hi,
I have the following problem : Area of a triangle is given by S = 1/2 ab sin(γ) (See figure).
Discuss numeric conditioning of S. Any tips appreciated :D
View attachment 2493
 

Attachments

  • triangle.png
    triangle.png
    2.8 KB · Views: 98
Physics news on Phys.org
natalia said:
Hi,
I have the following problem : Area of a triangle is given by S = 1/2 ab sin(γ) (See figure).
Discuss numeric conditioning of S. Any tips appreciated :D
https://www.physicsforums.com/attachments/2493

Hi natalia! ;)

I'm not quite sure what is intended with numeric conditioning...
Can you clarify?

What I can imagine is that we'd like to know how errors in $a, b, γ$ propagate.
The general formula for the absolute error is:
$$\Delta y \approx \frac{dy}{dx} \Delta x$$
For the relative error (as you might deduce) it is:
$$\frac{\Delta y}{y} \approx \frac x y \frac{dy}{dx} \frac{\Delta x} x$$

In your problem you would get:
For the contribution of $\Delta a$: $\frac{\Delta S}S = \frac{\Delta a}a$
For the contribution of $\Delta b$: $\frac{\Delta S}S = \frac{\Delta b}b$
For the contribution of $\Delta γ$: $\Delta S = \frac 1 2 a b \cos γ \Delta γ$
 
Yes, it refers to amplification of the relative error.
 
natalia said:
Yes, it refers to amplification of the relative error.

Aha! :D

Then, to complete it, we have for $Δγ$:

$$\frac{ΔS}{S}
= \frac{\frac 12 ab \cos γΔγ}{\frac 12 ab \sin γ}
= γ\cot γ \cdot \frac{Δγ}{γ}
$$

For small angles $γ$ this is approximately $\frac{Δγ}{γ}$.
 
Thank you again, I like Serena :)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 57 ·
2
Replies
57
Views
6K
  • · Replies 12 ·
Replies
12
Views
5K