Help Solving DE with Squared Term

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Hey guys,

Homework Statement


Solve the following DE,

y"+t(y')^2=0I'm not sure what to do with the square there. Would it help if i divided the whole equation by y'?

Thanks
 
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2RIP said:
y"+t(y')^2=0

Hey 2RIP! :smile:

HInt: put y' = v …

then it's v' + tv2 = 0. :wink:
 
tiny-tim said:
Hey 2RIP! :smile:

HInt: put y' = v …

then it's v' + tv2 = 0. :wink:

Oh thanks tiny-tim, it becomes a separable equation :P
 

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