Help Solving Trig Homework: Find cos(u+v)

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To find cos(u+v) given Sin(u)=√2/2 and cos(v)=4/5, the angle addition identity for cosine should be used. The correct formula is cos(u+v) = cos(u)cos(v) - sin(u)sin(v). With cos(u)=√2/2 and sin(u)=√2/2, and sin(v) calculated as √(1 - (4/5)²) = -3/5, the solution simplifies to cos(u+v) = (√2/2)(4/5) - (√2/2)(-3/5), resulting in 7√2/10. This method confirms that the problem requires applying the cosine addition formula rather than simple addition.
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Homework Statement



If Sin(u)=\frac{\sqrt{2}}{2} and cos(v)=\frac{4}{5} and

0≤ u ≤\frac{∏}{2} and \frac{3∏}{2}≤ v ≤ 2∏

find cos (u+v)

The Attempt at a Solution



cos(u)=\frac{\sqrt{2}}{2} and cos(v)=\frac{4}{5}

Do I just add them together? I feel like I'm missing something, but maybe the problem really is that simple.
 
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e^(i Pi)+1=0 said:

Homework Statement



If Sin(u)=\frac{\sqrt{2}}{2} and cos(v)=\frac{4}{5} and

0≤ u ≤\frac{∏}{2} and \frac{3∏}{2}≤ v ≤ 2∏

find cos (u+v)

The Attempt at a Solution



cos(u)=\frac{\sqrt{2}}{2} and cos(v)=\frac{4}{5}

Do I just add them together? I feel like I'm missing something, but maybe the problem really is that simple.
Use the angle addition identity for cosine .
 


So it would be..

(\frac{\sqrt{2}}{2})(\frac{4}{5})-(\frac{\sqrt{2}}{2})(\frac{-3}{5}) = \frac{7\sqrt{2}}{10}
 


Excellent!

ehild
 
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